From 9beeb46022fc1e0c6bc6bec029bb949df10a2c3d Mon Sep 17 00:00:00 2001 From: June McEnroe Date: Thu, 10 Jan 2019 20:19:51 -0500 Subject: Remove cash/tests --- bin/cash/tests/builtins/getopts1.0 | 25 ------------------------- 1 file changed, 25 deletions(-) delete mode 100644 bin/cash/tests/builtins/getopts1.0 (limited to 'bin/cash/tests/builtins/getopts1.0') diff --git a/bin/cash/tests/builtins/getopts1.0 b/bin/cash/tests/builtins/getopts1.0 deleted file mode 100644 index ceca459f..00000000 --- a/bin/cash/tests/builtins/getopts1.0 +++ /dev/null @@ -1,25 +0,0 @@ -# $FreeBSD: releng/12.0/bin/sh/tests/builtins/getopts1.0 297752 2016-04-09 16:06:13Z jilles $ - -printf -- '-1-\n' -set -- -abc -getopts "ab:" OPTION -printf '%s\n' "${OPTION}" - -# In this case 'getopts' should realize that we have not provided the -# required argument for "-b". -# Note that Solaris 10's (UNIX 03) /usr/xpg4/bin/sh, /bin/sh, and /bin/ksh; -# ksh93 20090505; pdksh 5.2.14p2; mksh R39c; bash 4.1 PL7; and zsh 4.3.10. -# all recognize that "b" is missing its argument on the *first* iteration -# of 'getopts' and do not produce the "a" in $OPTION. -printf -- '-2-\n' -set -- -ab -getopts "ab:" OPTION -printf '%s\n' "${OPTION}" -getopts "ab:" OPTION 3>&2 2>&1 >&3 3>&- -printf '%s\n' "${OPTION}" - -# The 'shift' is aimed at causing an error. -printf -- '-3-\n' -shift 1 -getopts "ab:" OPTION -printf '%s\n' "${OPTION}" -- cgit 1.4.1